qz1sol_7193f10

# qz1sol_7193f10 - π r Therefore the radius of the moon is r...

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TA: Tomoyuki Nakayama Monday, August 30, 2010 PHY 2048: Physic 1, Discussion Section7193 Quiz 1 (Homework Set #1) Name: UFID: Formula sheets are not allowed. Calculators are allowed. Do not store equations in your calculator. You need to show all of your work for full credit. ________________________________________________________________________________ The moon is approximately a sphere of circumference 1.09 ×10 7 m. a) What is its surface area in square kilometers? The circumference of a sphere is given by l = 2
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Unformatted text preview: π r. Therefore, the radius of the moon is r = l/(2 π ) = 1.73 × 10 6 m = 1.73 × 10 6 m × (1 km/1000 m) = 1.73 × 10 3 km The surface area of the moon is A = 4 π r 2 = 3.76 × 10 7 km 2 b) What is its volume in cubic miles? (1 mile = 1.609 km) First we express the radius of the moon in miles: r = 1.73 × 10 3 km = = 1.73 × 10 3 km × (1 mi/1.609 km) = 1.08× 10 3 mi The volume of the moon is V = (4/3) π r 3 = 5.28 × 10 9 mi 3...
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## This note was uploaded on 01/25/2011 for the course PHY 2048 taught by Professor Field during the Summer '08 term at University of Florida.

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