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Unformatted text preview: 0 = B b – W i W b The buoyancy on the block is equal to the weight of water displaced by the block. Therefore, W b = 0.85 ρ w V b g Expressing the buoyancy and gravitational forces in terms of volume and density, we solve the first equation for the mass of the block. 0 = 0.85 ρ w V b g – ρ i V i g – ρ b V b g ⇒ m i = ρ i V i = (0.85 ρ w – ρ b )V b = 2.08 kg b) What mass of iron is needed if the iron is attached to the bottom of the wood? Since the iron load is submerged in water, a buoyant force is exerted on it. The balance of forces equation yields 0 =B i + B b – W i W b 0 = ρ w V i g + 0.85 ρ w V b g – ρ i V i g – ρ b V b g V i = (0.85 ρ w – ρ b )V b /( ρ i  ρ w) = 3.03 × 104 m 3 The mass of the iron load is m i = ρ i V i =2.38 kg...
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This note was uploaded on 01/25/2011 for the course PHY 2048 taught by Professor Field during the Summer '08 term at University of Florida.
 Summer '08
 Field
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