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Unformatted text preview: a) What is the mass of the water pumped out from the basement in one second? During time interval t, the water moves x = v t in the hose. The mass of water flowing out of the hose in t is m = V = ( r 2 )v t Therefore, the mass of the water pumped out in one second is m/ t = ( r 2 )v = 1.21 kg b) What is the power of the pump? The power of the pump is defined as the work done by the pump in a unit time. The work energy yields P = W/ t = ( K + U)/ t = (1/2)( m/ t)v 2 + ( m/ t)gh = 51.4 W...
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This note was uploaded on 01/25/2011 for the course PHY 2048 taught by Professor Field during the Summer '08 term at University of Florida.
- Summer '08