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Unformatted text preview: ) It takes the maximum value of x m . Therefore, the maximum velocity is given by v m = x m . According to the graph, the maximum velocity is 25 cm/s. The angular frequency is = v m /x m = 5 rad/s b) What is the phase constant (from 0 to 2 rad) for the harmonic oscillator? The velocity and acceleration of the oscillator are v(t) = dx/dt = - v m sin( t + ) , a(t) = dv/dt = -a m cos( t + ) At time t = 0, the velocity takes the value v s = 20 cm/s. The velocity function yields v s = -v m sin( ) = sin-1 (-v s /v m ) = 4.07 rad, 5.36rad At time t = 0, the acceleration (i.e. the slope of the graph) is positive. The acceleration function yields -a m cos( ) &gt; 0 /2&lt; &lt;3 /2 Therefore, the phase constant is 4.07 rad....
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This note was uploaded on 01/25/2011 for the course PHY 2048 taught by Professor Field during the Summer '08 term at University of Florida.
- Summer '08