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Unformatted text preview: the bullet is embedded. a) What is the speed of the block just after the bullet is embedded in the block? During the collision between the bullet and block, the total momentum of the system is conserved. The momentum conservation equation yields mv = (M + m)V V = mv/(M + m) = 0.748 m/s b) What is the amplitude of the resulting simple harmonic motion? Once the bullet is embedded in the block, the mechanical energy of the system is conserved. The energy conservation equation yields (1/2)(M + m)V 2 = (1/2)kx m 2 x m = V [(M + m)/k] = 0.0374 m...
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 Summer '08
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