This preview shows page 1. Sign up to view the full content.
Unformatted text preview: 2 to the right and downward respectively. Newtons 2 nd law yields 1: m 1 a = T, 2:m 2 a = m 2 g T a = m 2 g/(m 1 + m 2 ) = 2.33 m/s 2 In the coordinate system given in the figure, the accelerations of m 1 and m 2 are a 1 = +2.33 i , a 2 = 2.33 j The acceleration of the center of mass is a com = (m 1 a 1 + m 2 a 2 )/(m 1 + m 2 ) = 1.78(m/s 2 ) i 0.555(m/s 2 ) j b) In unitvector notation, what is the com of the system as a function of time t ? The velocity of the center of mass is v com = v com,0 + a com dt = 1.78t i 0.555t j The center of mass of the system is initially located at x com,0 = (m 1 x 1,0 + m 2 x 2,0 )/(m 1 + m 2 )= 0.457 i 0.0476 j The center of mass of the system is x com = x com,0 + v com dt = (0.457 + 0.89t 2 )(m) i + (0.0476 0.275t 2 )(m) j...
View
Full
Document
This note was uploaded on 01/25/2011 for the course PHY 2048 taught by Professor Field during the Summer '08 term at University of Florida.
 Summer '08
 Field
 Work

Click to edit the document details