Unformatted text preview: 2 to the right and downward respectively. Newton’s 2 nd law yields 1: m 1 a = T, 2:m 2 a = m 2 g – T ⇒ a = m 2 g/(m 1 + m 2 ) = 2.33 m/s 2 In the coordinate system given in the figure, the accelerations of m 1 and m 2 are a 1 = +2.33 i , a 2 = 2.33 j The acceleration of the center of mass is a com = (m 1 a 1 + m 2 a 2 )/(m 1 + m 2 ) = 1.78(m/s 2 ) i – 0.555(m/s 2 ) j b) In unitvector notation, what is the com of the system as a function of time t ? The velocity of the center of mass is v com = v com,0 + ∫ a com dt = 1.78t i – 0.555t j The center of mass of the system is initially located at x com,0 = (m 1 x 1,0 + m 2 x 2,0 )/(m 1 + m 2 )= 0.457 i – 0.0476 j The center of mass of the system is x com = x com,0 + ∫ v com dt = (0.457 + 0.89t 2 )(m) i + (0.0476 – 0.275t 2 )(m) j...
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 Summer '08
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 Mass, Work, unitvector notation, xy coordinates, Tomoyuki Nakayama

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