qz7sol_7193f10 - Δθ = 3 rev ×(2 π rad/1 rev = 6 π rad...

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TA: Tomoyuki Nakayama Monday, October 18, 2010 PHY 2048: Physic 1, Discussion Section7193 Quiz 7 (Homework Set #8) Name: UFID: Formula sheets are not allowed. Calculators are allowed. Do not store equations in your calculator. You need to show all of your work for full credit. ________________________________________________________________________________ A merry-go-round rotates from rest with an angular acceleration of 1.60 rad/s 2 . a) How long does it take to rotate through the first 3.00 rev? First we express the angular displacement of the merry-go-round in radians.
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Unformatted text preview: Δθ = 3 rev × (2 π rad/1 rev) = 6 π rad One of the kinematics equations yields Δθ = (1/2) α t 2 ⇒ t = √ (2 Δθ / α ) = 4.85 s b) How long does it take to rotate through the next 3.00 rev? We calculate the time interval for the merry-go-round to rotate the first 6 rev. Δθ = 6 rev × (2 π rad/1 rev) = 12 π rad Δθ = (1/2) α t 2 t = √ (2 Δθ / α ) = 6.86 s From a), we know it takes 4.85 s to rotate the first 3 rev. The time it takes to rotate the second 3 rev is 6.86 – 4.85 = 2.01 s...
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This note was uploaded on 01/25/2011 for the course PHY 2048 taught by Professor Field during the Summer '08 term at University of Florida.

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qz7sol_7193f10 - Δθ = 3 rev ×(2 π rad/1 rev = 6 π rad...

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