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Unformatted text preview: displacement of the ball is h 2 . The flight time of the projectile motion is -h = -(1/2)gt 2 t = (2h 2 /g) = 0.143 s During this time interval, the horizontal displacement is d. The velocity of the shell at the edge is d = v t v = d/t = 1.40 m/s b) With what speed is the spherical shell shot at point P ? While the shell rolls on the surface, the mechanical energy of the shell is conserved. For a smooth rolling, the velocity of the center of mass of a rolling object and its angular velocity are related as v = r . The speed ot the shell at point P is E i = E f (1/2)mv 2 + (1/2)I 2 = (1/2)mv 2 + (1/2)I 2 + mgh 1 (1/2)mv 2 + (1/2)(2/3)mr 2 (v/r) 2 = (1/2)mv 2 + (1/2)(2/3)mr 2 (v/r) 2 + mgh 1 v = (v 2 + 6gh 1 /5) = 2.21 m/s...
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- Summer '08