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qz9sol_3891f10 - φ = 20º The strut is in equilibrium...

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TA: Tomoyuki Nakayama Tuesday, November 2, 2010 PHY 2048: Physic 1, Discussion Section 3891 Quiz 9 (Homework Set #10) Name: UFID: Formula sheets are not allowed. Calculators are allowed. Do not store equations in your calculator. You need to show all of your work for full credit. ________________________________________________________________________________ The system in the figure below right is in equilibrium. A concrete block of mass 400 kg hangs from the end of the uniform strut of mass 150 kg. The angles in the figure are φ = 25.0° and θ = 45.0°. a) What is the tension T in the cable? The angle between the cable and the strut is θ φ
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Unformatted text preview: φ = 20º. The strut is in equilibrium. Therefore, the net torque exerted on the strut is zero. We choose our rotational axis at the hinge. The balance of torques equation yields -mg(L/2)cos θ – MgLcos θ + Tsin( θ – φ )L = 0 ⇒ T = (M + m/2)gcos θ /sin( θ – φ ) = 9.62× 10 3 N b) What are the horizontal and vertical components of the force on the strut from the hinge? Since the strut is in equilibrium, the net force exerted on the strut is zero. The balance of forces equation yields x: F x – Tcos φ = 0 F x = Tcos φ = 8.72 × 10 3 N y: F y – mg – Mg – Tsin φ = 0 F y = mg + Mg + Tsin φ = 9.46 × 10 3 N...
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