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Old Final

# Old Final - CHM 2046 Gower Sections Final Exam(Form Code A...

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CHM 2046 Gower Sections Final Exam (Form Code A) Fall 2009 Instructions: On your scantron sheet enter and bubble in your name , UF ID number (start on the leftmost space and leave any extra spaces blank), and Form Code (see above). Turn in only your scantron. Check your bubbling carefully bubbling errors will not be negotiated . Note: The double-arrow symbol used in this exam ( ↔) refers to a reversible reaction. Potentially Useful Information: K w = 1.0 x 10 14 R = 0.0821 lit•atm/mol•K and 8.314 J/mol•K 1 A = 1 C/s 1 F = 96,500 C/mol e - c = 3.00 x 10 8 m/s 1 kg = 6.022 x 10 26 amu 1 J = 1 kg•m 2 /s 2 1. The equilibrium constant K c for the reaction I 2 (g) ↔ 2I is 3.8 x 10 5 at 727ºC. What is the K c for the reaction 2I(g) ↔ I 2 (g) at the same temperature? (1) 2.6 x 10 4 (2) 1.4 x 10 9 (3) 1.9 x 10 5 (4) 3.8 x 10 5 (5) 6.8 x 10 3 2. Consider the following equilibrium in a closed container: C (graphite) + 2H 2(g) CH 4(g) Δ H º = 75 kJ An increase in temperature will…. (1) decrease the partial pressure of H 2 , increase the partial pressure of CH 4 , and increase the K p (2) decrease the partial pressure of H 2 , increase the partial pressure of CH 4 , and decrease the K p (3) increase the partial pressure of H 2 , decrease the partial pressure of CH 4 , and increase the K p (4) increase the partial pressure of H 2 , decrease the partial pressure of CH 4 , and decrease the K p (5) decrease the partial pressure of H 2 , increase the partial pressure of CH 4 , and K p will stay the same 3. Calculate the mass (in grams) of solid benzoic acid (C 6 H 5 COOH) you would need, in order to prepare 1.0 liter of benzoic acid/benzoate buffer of pH 4.00, using a stock 0.050 M sodium benzoate (C 6 H 5 COONa) solution. The K a of benzoic acid is 6.3 x 10 5 . (1) 13 g (2) 9.7 g (3) 7.4 g (4) 5.3 g (5) 2.4 g 4. Calculate the mass (in mg) of sodium acetate (CH 3 COONa) needed to make 200. mL of aqueous CH 3 COONa solution with a pH of 8.00. The K b of CH 3 COO = 5.6 x 10 10 .

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