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18. We determine each capacitance from the slope of the appropriate line in the graph.
Thus,
C
1
= (12
µ
C)/(2.0 V) = 6.0
µ
F.
Similarly,
C
2
= 4.0
µ
F and
C
3
= 2.0
µ
F.
The total
equivalent capacitance is given by
123
123
1
2
3
1
2
3
11
1
()
CCC
CC
C
C
C
C
C
+
+
=+
=
++
,
or
12
3
123
(6.0 F)(4.0 F 2.0 F)
36
F3
.
0
F
6
.
0F4
.
0F2
.
0F 1
2
CC C
C
µ
µµ
µµµ
+
+
==
=
=
+
+
.
This implies that the charge on capacitor 1 is
1
q
=
(3.0
µ
F)(6.0 V) = 18
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 Spring '10
 AS
 Physics, Capacitance

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