chapter25- 030 - 30(a The capacitance is C= 0 A d =(8.85 10...

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30. (a) The capacitance is () ( ) 12 2 2 4 2 11 0 3 8.85 10 C /N m 40 10 m 3.5 10 F 35pF. 1.0 10 m A C d ε −− ×⋅ × == = × = × (b) q = CV = (35 pF)(600 V) = 2.1 × 10 –8 C = 21 nC. (c) UC V = × 1 2 2 1 2 2 6 35 21 6 3 10 pF nC J = 6.3 J. b gb g . µ (d) E = V / d = 600 V/1.0
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This note was uploaded on 01/25/2011 for the course PHY 232 taught by Professor Yt during the Spring '10 term at The Petroleum Institute.

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