This preview shows page 1. Sign up to view the full content.
(b) and (c)
At
C
3
= 0, the graph indicates
V
1
= 2.0 V.
The above expression
consequently implies
C
1
= 4
C
2
.
Next we note that the graph shows that, at
C
3
= 6.0
µ
F,
the voltage across
C
1
is exactly half of the battery voltage.
Thus,
1
2
=
C
2
+ 6.0
µ
F
C
1
+
C
2
+ 6.0
µ
F
=
C
2
+ 6.0
µ
F
4
C
2
+
C
2
+ 6.0
µ
F
which leads to
C
2
= 2.0
µ
F.
We conclude, too, that
C
1
= 8.0
µ
F.
28. Initially the capacitors
C
1
,
C
2
, and
C
3
form a combination equivalent to a single
capacitor which we denote
This is the end of the preview. Sign up
to
access the rest of the document.
 Spring '10
 AC
 Physics

Click to edit the document details