chapter25- 027 - 27. (a) In this situation, capacitors 1...

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( ) ( ) ( ) 13 1.00 F 3.00 F 12.0V 9.00 C. 1.00 F+3.00 F CCV qq CC µµ µ == = = + (b) Capacitors 2 and 4 are also in series: ( ) ( ) ( ) 24 2.00 F 4.00 F 12.0V 16.0 C. 2.00 F 4.00 F = = ++ (c) 31 9.00 C. (d) 42 16.0 C. (e) With switch 2 also closed, the potential difference V 1 across C 1 must equal the potential difference across C 2 and is ( )( ) 34 1 1234 3.00 F 4.00 F 12.0V 8.40V. 1.00 F 2.00 F 3.00 F 4.00 F VV CCCC µµµµ + + = +++ + + + Thus, q 1 = C 1 V 1 = (1.00 F)(8.40 V) = 8.40 C. (f) Similarly,
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This note was uploaded on 01/25/2011 for the course PHYS 244 taught by Professor Ac during the Spring '10 term at The Petroleum Institute.

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