26. The charges on capacitors 2 and 3 are the same, so these capacitors may be replaced by an equivalent capacitance determined from 11 1 23 23 23 CC C CC CC eq =+= + . Thus, C eq = C 2 C 3 /(C 2 + C 3 ). The charge on the equivalent capacitor is the same as the charge on either of the two capacitors in the combination and the potential difference across the equivalent capacitor is given by q 2 /C eq . The potential difference across capacitor 1 is q1 / C 1 , where q1is the charge on this capacitor. The potential difference across the combination of capacitors 2 and 3 must be the same as the potential difference across capacitor 1, so q 1 /C 1 = q2/ C eq . Now some of the charge originally on capacitor 1 flows to the combination of 2 and 3. If q0 is the original charge, conservation of charge yields q 1 + q2= q
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