HW_8_solutions

HW_8_solutions - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 91E 1 mar FinLI ‘i’fl in the new-uric in Fig. Pill—l. Figure Pm; SOLUTION: 12 owe KVL’- (H11): +leL—‘S law” KVL: Jlf, +31; :0 (mg) i, + J! E: l2£0° JIT, -l 31‘ z: o L '1’. :54'56‘3PA $2; --= 2( reel—M6 3:0) VD: 3'314'lVG-Slov Chapter 10: Magnetically Coupled Networks Problem 10.7 Inn/in. Basic Engineering Circuit Analysis, 9/E 1 1mg Fiml 1‘0 in lhe circuit in Fig. PlIHJ. Figure P1119 SOLUTION: Kuu J" T, + (Mini :0 (2+JL) I, + Jlil ‘—' I010” J'T,‘+(HJ3)T ; l I; = 3-11 —3QDA 32 : H‘Iz. isr-‘Irw‘m _____________.__._—.~.—~———-———-————— Chapter 10: Magnetically Coupled Networks Problem 10.9 2 Inivin, Basic Engineering Circuit Analysis, 9/E \70: l(l-I74 i5q-LN°) V0: l'l7/.IS'Cl-LN°\/ _________________.___..__.._—.———- Problem 10.9 Chapter 10: Magnetically Coupled Networks Irwin, Basic Engineering Circuit Analysis, 9/E 1 10.10 Write the mesh ellilutinna [111' the network in Fig. Pill. ] I} 21ml determine Tag” 1"]. .. —j1 n - 2113'; y” Figure Fm.1e SOLUTION: Chapter 10: Magnetically Coupled Networks Problem 10.10 Irwin, Basic Engineering Circuit Analysis, 9/E <7. Q—J‘i V0 : 2 ___________________._____————————————- Problem 10.10 Chapter 10: Magnetically Coupled Networks Irwin, Basic Engineering Circuit Analysis, 9/E 10,11. Fiml I131:1th circuit in Fig. PIIH l. {an 2n, Fifi /" \ fan I‘ I + 34_‘-’|:J_r ----_ anti gar: 4:1 1. r H Figure Fun SOLUTION: I<VLr (2-J1)T,+J2T1= 2L//_o° I<vu j2i,+ [6+J2)‘f2 +j2~=f3zo KUL‘ jail +(124J'8)T3 :o (2..J'1)f, +jzfz : aqua” J'zf, ~+ {6+J2)fz+ J21} =0 121+ (12418)T3:o j: ”H 4%).ch __________________________———————————— Chapter 10: Magnetically Coupled Networks Problem 10.11 Irwin, Basic Engineering Circuit Analysis. 9/E 2 ‘3 .-.: Gaul/69' 8Q°A V0 = ‘41: VD2 L{(0303 063.920) \70: 1'1! A warmw —______———————————————————‘—‘—— a Problem 10.11 Chapter 10: Magnetically Coupled Networks Irwin, Basic Engineering Circuit Analysis, 9/E ‘ 1 1030 [h‘lcrmiuc 10 in the Jictwm'k in Fig. F'HLEII'. Figure No.20 SOLUTION: ~11 n ’2: Effijzfo o: 3251'. +1: Chapter 10: Magnetically Coupled Networks Problem 10.20 2 Irwin. Basic Engineering Circuit Analysis. 9/E ____________________._.————————— Problem 10.20 _ Chapter 10: Magnetically Coupled Networks Irwin, Basic Engineering Circuit Analysis, 9/E ‘ 1 10.24 Find V0 in the notwnrk in Fig. Pllflal. _,r'2 [1 F! i mark-v i eon-fir: Figure Filmer. SOLUTION: KVL‘ QO'J'Q) I1 UIOTL: IOOLO°~20040° (lo—Jro) f, V‘J'loz‘fL : *lovo° KVL'. J'roi —J'r5f7_ 159.13 = 20040“ KVL: 'JZTL+ (2+jl)f3:o (toejlo) f] + J’ IOTL: ~looLO° J“): ~J5TL ~j2f3: 200L6° Chapter 10: Magnetically Coupled Networks Problem 10.24 2 Inn/in. Basic Engineering Circuit Analysis, 9/E “JZTL f (2+J'L)f3:0 5 L ‘~'-' I631 thew/x (JD : 207384 72 47°) V0: 3676 4724‘” v __——_—___—__—._———————————_—-—— Problem 10.24 Chapter 10: Magnetically Coupled Networks ...
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