hw03a - aldawsari (ma28683) HW03 Betancourt (16856) 1 This...

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Unformatted text preview: aldawsari (ma28683) HW03 Betancourt (16856) 1 This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 22.1-22.4 001 (part 1 of 3) 10.0 points An electric field of magnitude 4440 N / C is applied along the x axis. Calculate the electric flux through a rect- angular plane 0 . 155 m wide and 1 . 08 m long if the plane is parallel to the yz plane. Correct answer: 743 . 256 N m 2 / C. Explanation: Let : E = 4440 N / C , = 0 , L = 1 . 08 m , and W = 0 . 155 m . The area of the rectangle is A = L W = (1 . 08 m) (0 . 155 m) = 0 . 1674 m 2 . Since the field is uniform,the flux is = E A = E A cos = (4440 N / C) (0 . 1674 m 2 ) (cos0 ) = 743 . 256 N m 2 / C . 002 (part 2 of 3) 10.0 points Calculate the electric flux through the same rectangle, if it is parallel to the xy plane. Correct answer: 0 N m 2 / C. Explanation: The angle is = 90 ,cos = 0 , and = E A = E A cos = (4440 N / C) (0 . 1674 m 2 ) (0) = 0 N m 2 / C . 003 (part 3 of 3) 10.0 points Calculate the electric flux through the same rectangle, but now the rectangle contains the y axis and its normal makes an angle of 60 with the x axis. Correct answer: 371 . 628 N m 2 / C. Explanation: Let = 60 = E A = E A cos = (4440 N / C) (0 . 1674 m 2 ) (cos 60 ) = 371 . 628 N m 2 / C ....
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This note was uploaded on 01/27/2011 for the course PHYS 251 taught by Professor Gavrine during the Spring '10 term at Purdue University-West Lafayette.

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hw03a - aldawsari (ma28683) HW03 Betancourt (16856) 1 This...

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