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hw09a - aldawsari(ma28683 HW09 Betancourt(16856 This...

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aldawsari (ma28683) – HW09 – Betancourt – (16856) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 26.3-26.4 001 10.0 points 5 . 1 Ω 4 . 1 Ω 18 . 4 Ω 26 . 6 V 13 . 3 V Find the current through the 18 . 4 Ω lower- right resistor. Correct answer: 0 . 93007 A. Explanation: r 1 r 2 R E 1 E 2 A D E B C F i 1 i 2 I Let : E 1 = 26 . 6 V , E 2 = 13 . 3 V , r 1 = 5 . 1 Ω , r 2 = 4 . 1 Ω , and R = 18 . 4 Ω . From the junction rule, I = i 1 + i 2 . Applying Kirchhoff’s loop rule, we obtain two equations: E 1 = i 1 r 1 + I R (1) E 2 = i 2 r 2 + I R = ( I - i 1 ) r 2 + I R = - i 1 r 2 + I ( R + r 2 ) , (2) Multiplying Eq. (1) by r 2 , Eq. (2) by r 1 , E 1 r 2 = i 1 r 1 r 2 + r 2 I R E 2 r 1 = - i 1 r 1 r 2 + I r 1 ( R + r 2 ) Adding, E 1 r 2 + E 2 r 1 = I [ r 2 R + r 1 ( R + r 2 )] I = E 1 r 2 + E 2 r 1 r 2 R + r 1 ( R + r 2 ) = (26 . 6 V) (4 . 1 Ω) + (13 . 3 V) (5 . 1 Ω) (4 . 1 Ω) (18 . 4 Ω) + (5 . 1 Ω) (18 . 4 Ω + 4 . 1 Ω) = 0 . 93007 A . 002 (part 1 of 2) 10.0 points The switch has been open for a long period of time. C R 2 R 1 V S Immediately after the switch is closed, the current supplied by the battery is 1. I 0 = V R 1 + R 2 . 2. I 0 = 0 . 3. I 0 = V R 2 . 4. I 0 = V R 1 . correct 5. I 0 = V ( R 1 + R 2 ) R 1 R 2 . Explanation: Before the switch is closed, there is no charge on the capacitor, so the voltage is zero across the capacitor at this time. Because it is not possible to change the charge on the
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