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Unformatted text preview: aldawsari (ma28683) – HW16 – Betancourt – (16856) 1 This printout should have 13 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 31.131.6 001 (part 1 of 2) 10.0 points When a particular inductor is connected to a sinusoidal voltage with a 226 V amplitude, a peak current of 1 . 7 A appears in the inductor. What is the maximum current if the fre quency of the applied voltage is doubled? Correct answer: 0 . 85 A. Explanation: Let : I max = 1 . 7 A . The current in the circuit is I max = V max X L = V max ω L . When the frequency is doubled, the current is I new = V max 2 ω L = 1 2 I max = 1 2 1 . 7 A = . 85 A . 002 (part 2 of 2) 10.0 points What is the inductive reactance at the new frequency? Correct answer: 265 . 882 Ω. Explanation: The inductive reactance is X L,new = V max I new = 226 V . 85 A = 265 . 882 Ω . 003 (part 1 of 2) 10.0 points In the purely inductive circuit in the figure below, the inductance is 46 . 2 mH and the rms voltage is 111 V. E = E max sin ωt E rms = 111 V S 46 . 2 mH Find the inductive reactance if the fre quency is 16 . 7 Hz. Correct answer: 4 . 84773 Ω....
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This note was uploaded on 01/27/2011 for the course PHYS 251 taught by Professor Gavrine during the Spring '10 term at Purdue.
 Spring '10
 Gavrine

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