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# hw18b - aljabr(faa335 Hw18 Ross(89251 This print-out should...

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aljabr (faa335) – Hw18 – Ross – (89251) 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 3) 10.0 points A 27 . 7 mA current is carried by a uniformly wound air-core solenoid with 285 turns as shown in the figure below. The permeability of free space is 1 . 25664 × 10 - 6 N / A 2 . 27 . 7 mA 14 . 4 mm 16 . 1 cm Compute the magnetic field inside the solenoid. Correct answer: 6 . 16181 × 10 - 5 T. Explanation: Let : N = 285 , = 16 . 1 cm , I = 27 . 7 mA , and μ 0 = 1 . 25664 × 10 - 6 N / A 2 . I d The magnetic field inside the solenoid is B = μ 0 n I = μ 0 parenleftbigg N parenrightbigg I = (1 . 25664 × 10 - 6 N / A 2 ) parenleftbigg 285 0 . 161 m parenrightbigg × (0 . 0277 A) = 6 . 16181 × 10 - 5 T . 002 (part 2 of 3) 10.0 points Compute the magnetic flux through each turn. Correct answer: 1 . 00351 × 10 - 8 Wb. Explanation: Let : B = 6 . 16181 × 10 - 5 T , and d = 14 . 4 mm = 0 . 0144 m . The magnetic flux through each turn is Φ = B A = B parenleftBig π 4 d 2 parenrightBig = (6 . 16181 × 10 - 5 T) π 4 (0 . 0144 m) 2 = 1 . 00351 × 10 - 8 Wb . 003 (part 3 of 3) 10.0 points Compute the inductance of the solenoid. Correct answer: 0 . 10325 mH. Explanation: The inductance of the solenoid is L = N Φ I = (285) (1 . 00351 × 10 - 8 Wb) 0 . 0277 A = 0 . 10325 mH . 004 (part 1 of 2) 10.0 points A solenoid has 129 turns of wire uniformly wrapped around an air-filled core, which has a diameter of 8 mm and a length of 7 . 4 cm. The permeability of free space is 1 . 25664 × 10 - 6 N / A 2 . Calculate the self-inductance of the solenoid. Correct answer: 1 . 42045 × 10 - 5 H. Explanation: Let : N = 129 , D = 8 mm = 0 . 008 m , = 7 . 4 cm = 0 . 074 m , and μ 0 = 1 . 25664 × 10 - 6 N / A 2 .

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aljabr (faa335) – Hw18 – Ross – (89251) 2 The self-inductance of a solenoid is given by L 1 = N Φ I , where Φ is the total flux inside the solenoid and I is the current in the wire wrapped around the solenoid.
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