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aljabr (faa335) – Hw19 – Ross – (89251)
1
This printout should have 13 questions.
Multiplechoice questions may continue on
the next column or page – Fnd all choices
before answering.
001
(part 1 of 2) 10.0 points
In the purely inductive circuit in the Fgure
below, the inductance is 10
.
3 mH and the
rms
voltage is 169 V.
E
=
E
max
sin
ωt
E
rms
= 169 V
S
10
.
3 mH
±ind the inductive reactance if the fre
quency is 8
.
3 Hz.
Correct answer: 0
.
53715 Ω.
Explanation:
Let :
f
= 8
.
3 Hz
,
and
L
= 10
.
3 mH = 0
.
0103 H
.
The angular frequency is
ω
= 2
π f ,
so the inductive reactance at 8
.
3 Hz is
X
L
=
ω L
= 2
π f L
= 2
π
(8
.
3 Hz) (0
.
0103 H)
=
0
.
53715 Ω
.
002
(part 2 of 2) 10.0 points
±ind the
rms
current in the circuit.
Correct answer: 314
.
624 A.
Explanation:
Let :
V
rms
= 169 V
.
The
rms
current is
I
rms
=
V
rms
X
L
=
169 V
0
.
53715 Ω
=
314
.
624 A
.
003
(part 1 of 2) 10.0 points
When a particular inductor is connected to a
sinusoidal voltage with a 136 V amplitude, a
peak current of 7
.
6 A appears in the inductor.
What is the maximum current if the fre
quency of the applied voltage is doubled?
Correct answer: 3
.
8 A.
Explanation:
Let :
I
max
= 7
.
6 A
.
The current in the circuit is
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This note was uploaded on 01/27/2011 for the course PHYS 251 taught by Professor Gavrine during the Spring '10 term at Purdue UniversityWest Lafayette.
 Spring '10
 Gavrine

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