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# hw19b - aljabr(faa335 Hw19 Ross(89251 This print-out should...

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aljabr (faa335) – Hw19 – Ross – (89251) 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points In the purely inductive circuit in the figure below, the inductance is 10 . 3 mH and the rms voltage is 169 V. E = E max sin ωt E rms = 169 V S 10 . 3 mH Find the inductive reactance if the fre- quency is 8 . 3 Hz. Correct answer: 0 . 53715 Ω. Explanation: Let : f = 8 . 3 Hz , and L = 10 . 3 mH = 0 . 0103 H . The angular frequency is ω = 2 π f , so the inductive reactance at 8 . 3 Hz is X L = ω L = 2 π f L = 2 π (8 . 3 Hz) (0 . 0103 H) = 0 . 53715 Ω . 002 (part 2 of 2) 10.0 points Find the rms current in the circuit. Correct answer: 314 . 624 A. Explanation: Let : V rms = 169 V . The rms current is I rms = V rms X L = 169 V 0 . 53715 Ω = 314 . 624 A . 003 (part 1 of 2) 10.0 points When a particular inductor is connected to a sinusoidal voltage with a 136 V amplitude, a peak current of 7 . 6 A appears in the inductor. What is the maximum current if the fre- quency of the applied voltage is doubled? Correct answer: 3 . 8 A. Explanation: Let : I max = 7 . 6 A . The current in the circuit is I max = V max X L = V max ω L .

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