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aljabr (faa335) – Hw21 – Ross – (89251)
1
This printout should have 12 questions.
Multiplechoice questions may continue on
the next column or page – Fnd all choices
before answering.
001
10.0 points
In the Fgure, a ray of light enters the liquid
from air and is bent toward the normal as
shown.
10
13
.
3
13
.
3
10
n
What is the index of refraction
n
for the
liquid?
Correct answer: 1
.
33.
Explanation:
Let :
a
= 13
.
3
,
and
b
= 10
.
b
a
a
b
c
c
θ
1
θ
2
Basic Concept:
Snell’s Law:
n
1
sin
θ
1
=
n
2
sin
θ
2
Solution:
Since the light is incident in air,
which has an index of refraction of
n
1
= 1
,
and
sin
θ
1
=
a
c
sin
θ
2
=
b
c
,
so
1
a
c
=
n
b
c
n
2
=
a
c
c
b
=
a
b
=
13
.
3
10
=
1
.
33
,
and
θ
1
= arctan
p
a
b
P
= arctan
±
13
.
3
10
²
= 53
.
0612
◦
θ
2
= arctan
±
b
a
²
= arctan
±
10
13
.
3
²
= 36
.
9388
◦
.
002
(part 1 of 3) 10.0 points
The wavelength of red light in air is 376 nm
.
What is its frequency?
Correct answer: 7
.
9732
×
10
14
Hz.
Explanation:
The relationship of speed of light, its wave
length and its frequency is
c
=
f λ ,
so the frequency is
f
=
c
λ
=
(2
.
99792
×
10
8
m
/
s)
(376 nm) (1
×
10
−
9
m
/
nm)
=
7
.
9732
×
10
14
Hz
.
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2
003
(part 2 of 3) 10.0 points
What is its wavelength in glass that has an
index of refraction of 1
.
5?
Correct answer: 250
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 Spring '10
 Gavrine
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