hw22a - aldawsari (ma28683) HW22 Betancourt (16856) 1 This...

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Unformatted text preview: aldawsari (ma28683) HW22 Betancourt (16856) 1 This print-out should have 7 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 17.6-17.7 001 10.0 points Given: specific heat of water = 1 cal / (g C) . How much heat is required to vaporize a(n) 8 g ice cube initially at 0 C? The latent heat of fusion of ice is 80 cal / g and the latent heat of vaporization of water is 540 cal / g. Correct answer: 5760 cal. Explanation: Given : m = 8 g , c = 1 cal / (g C) , L f = 80 cal / g , L v = 540 cal / g , and T = 100 C . The ice must be melted ( Q = mL f ), then the temperature of the water must be raised 100 C ( Q = mc T ), then the water must be vaporized ( Q = mL v ). Thus the heat required is Q = mL f + mc T + mL v = (8 g) (80 cal / g) + (8 g) (1 cal / (g C)) (100 C) + (8 g) (540 cal / g) = 5760 cal . 002 10.0 points A 36 g ice cube at- 13 C is dropped into a container of water at 0 C . How much water freezes onto the ice? The specific heat of ice is 0 . 5 cal / g C and the heat of fusion of is 80 cal / g. Correct answer: 2 . 925 g. Explanation: Given : m ice = 36 g , c v = 0 . 5 cal / g C , L f = 80 cal / g , T = 0 C , and T i =- 13 C ....
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This note was uploaded on 01/27/2011 for the course PHYS 251 taught by Professor Gavrine during the Spring '10 term at Purdue University-West Lafayette.

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hw22a - aldawsari (ma28683) HW22 Betancourt (16856) 1 This...

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