This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: aljabr (faa335) Hw22 Ross (89251) 1 This printout should have 13 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points An object is p = 48 cm in front of a concave mirror. Its real image height is 6 times larger than the object height. p h What is the location of the image? Correct answer: 288 cm. Explanation: 1 p + 1 q = 1 f = 2 R m = h h = q p Concave Mirror f > >p> f f <q < >m> f >p> <q < >m> 1 Let : M = 6 and p = 48 cm . Let the location of the image be denoted as q . q p h h' f R Since the image is 6 times larger than the object, and is a real image, as stated in the problem ( p > 0 and q > 0), the magnification must be negative; i.e. , M = 6. M = h h = q p = 6 , so q = M p = ( 6) (48 cm) = 288 cm . 002 (part 2 of 2) 10.0 points What is the radius of curvature of the mirror? Correct answer: 82 . 2857 cm. Explanation: Now that we have q and p , we can find the radius of the curvature via the relationship 1 p + 1 q = 2 R or R = 2 pq p + q = 2 (48 cm) (288 cm) 48 cm + 288 cm = 82 . 2857 cm . 003 10.0 points A concave mirror has a focal length of 51 . 9 cm. Determine the object position for which the resulting image is upright and four times the size of the object. Correct answer: 38 . 925 cm....
View
Full
Document
This note was uploaded on 01/27/2011 for the course PHYS 251 taught by Professor Gavrine during the Spring '10 term at Purdue UniversityWest Lafayette.
 Spring '10
 Gavrine

Click to edit the document details