This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: aldawsari (ma28683) HW24 Betancourt (16856) 1 This printout should have 12 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 19.119.8 001 (part 1 of 2) 10.0 points One mole of an ideal gas does 3499 J of work on the surroundings as it expands isother mally to a final pressure of 1 . 1 atm and vol ume of 27 L. Determine the initial volume.( R = 8 . 31451 J / K mol.) Correct answer: 8 . 43881 L. Explanation: Given : n = 1 mol , W = 3499 J , R = 8 . 31451 J / K mol , P f = 1 . 1 atm , and V f = 27 L . By the ideal gas law, P V = nRT . The work done in an isothermal process is W = nRT ln parenleftbigg V f V i parenrightbigg = P V ln parenleftbigg V f V i parenrightbigg ln parenleftbigg V f V i parenrightbigg = W P V V f V i = e W/ ( P V ) V i = V f e W/ ( P V ) Since W PV = 3499 J (1 . 1 atm) (1 . 013 10 5 ) (27 L) (1 10 3 ) = 1 . 163 V i = (27 L) e ( 1 . 163) = 8 . 43881 L . 002 (part 2 of 2) 10.0 points Determine the temperature of the gas. Correct answer: 361 . 851 K. Explanation: According to the equation of state for an ideal gas, the temperature is T f = P f V f nR = (1 . 1 atm)(1 . 013 10 5 )(27 L)(1 e 3) (1 mol)(8 . 31451 J / K mol) = 361 . 851 K ....
View Full
Document
 Spring '10
 Gavrine

Click to edit the document details