hw25b - aljabr (faa335) Hw25 Ross (89251) 1 This print-out...

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Unformatted text preview: aljabr (faa335) Hw25 Ross (89251) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points The density of gasoline is 730 kg / m 3 at 0 C. One gallon of gasoline occupies 0 . 0038 m 3 . Gasolines volume expansion coefficient is . 00096 C 1 . How many extra kilograms of gasoline are obtained when nine gallons of gasoline are bought at 0 C rather than at 27 C (tempera- ture at the filling station)? Correct answer: 0 . 630769 kg. Explanation: Given : = 730 kg / m 3 , T = 0 C , T 1 = 27 C , = 0 . 00096 C 1 , 1 gallon = 0 . 0038 m 3 , and V = (9 gallons) parenleftbigg . 0038 m 3 gallon parenrightbigg = 0 . 0342 m 3 . The specific volume is V = 1 , then V = V T . The change in volume is V = V T = (9 gallons) (0 . 00096 C 1 ) (27 C) parenleftbigg . 0038 m 3 gallon parenrightbigg = 0 . 000886464 m 3 . The expanded specific volume of the gaso- line is V = V + V , which gives 1 = 1 + T , inverting = 1 + T , where is the density of the gasoline at the higher temperature. Hence, the change in mass of gasoline for a constant defined gallon volume V (at 27 C rather than 0 C) is given by m = V- V = V parenleftbigg 1- 1 1 + T parenrightbigg = V T 1 + T = V 1 + T = ( 730 kg / m 3 ) ( . 000886464 m 3 ) 1 + (0 . 00096 C 1 ) (27 C) = . 630769 kg . If you calculate the answer using the expres- sion m = V = ( 730 kg / m 3 ) ( . 000886464 m 3 ) = 0 . 647119 kg . you are wrong (close counts in horse-shoes and hand-grenades). The density, expansion coefficient, and conversion factor for gallons to m 3 is given at T = 0 C , not T = 27 C . 002 (part 1 of 2) 10.0 points At 8 C, an aluminum ring has an inner diam- eter of 2 cm and a brass rod has a diameter of 2 . 07 cm....
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hw25b - aljabr (faa335) Hw25 Ross (89251) 1 This print-out...

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