hw26a - aldawsari (ma28683) HW26 Betancourt (16856) 1 This...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: aldawsari (ma28683) HW26 Betancourt (16856) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 20.3-20.7 001 10.0 points The efficiency of a 905 MW nuclear power plant is 21 . 5%. If a river of flow rate 3 . 19 10 6 kg / s were used to transport the excess thermal energy away, what would be the average temperature increase of the river? Correct answer: 0 . 247451 C. Explanation: Given: P output = 905 MW = 9 . 05 10 8 W and e = 21 . 5% = 0 . 215 . The excess thermal energy transported per second by the river is P excess = P input (1- e ) = parenleftbigg P output e parenrightbigg (1- e ) = parenleftbigg 9 . 05 10 8 W . 215 parenrightbigg (1- . 215) = 3 . 3043 10 9 W where e is the efficiency and P output the power output of the plant. Thus the temperature of the river is increased (per second) by d m d t c T = d Q d t = P excess where c is the heat capacity of water and...
View Full Document

This note was uploaded on 01/27/2011 for the course PHYS 251 taught by Professor Gavrine during the Spring '10 term at Purdue University-West Lafayette.

Page1 / 3

hw26a - aldawsari (ma28683) HW26 Betancourt (16856) 1 This...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online