aljabr (faa335) – Hw26 – Ross – (89251)
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001
10.0 points
Given:
The specific heat of air is approxi
mately 1 kJ
/
kg
·
◦
C. Take the density of air
to 1
.
25 kg
/
m
3
. The specific heat of water is
4
.
19 kJ
/
kg
·
◦
C and the density of water is
1000 kg
/
m
3
.
The air temperature above the coastal areas
is profoundly influenced by the large specific
heat of water.
One reason is that the heat released when
2 m
3
of water cools by 2
◦
C will raise the
temperature of an enormously larger volume
of air by 3
◦
C.
Calculate this volume of air.
Correct answer: 4469
.
33 m
3
.
Explanation:
Given :
V
w
= 2 m
3
,
c
w
= 4
.
19 kJ
/
kg
·
◦
C
,
ρ
w
= 1000 kg
/
m
3
,
c
air
= 1 kJ
/
kg
·
◦
C
,
ρ
air
= 1
.
25 kg
/
m
3
,
Δ
T
w
= 2
◦
C
,
and
Δ
T
air
= 3
◦
C
.
ρ
w
V
w
c
w
Δ
T
w
=
ρ
air
V
air
c
air
Δ
T
air
V
air
=
ρ
w
V
w
c
w
Δ
T
w
ρ
air
c
air
Δ
T
air
=
(1000 kg
/
m
3
)(2 m
3
)
1
.
25 kg
/
m
3
×
(4
.
19 kJ
/
kg
·
◦
C) (2
◦
C)
(1 kJ
/
kg
·
◦
C) (3
◦
C)
= 4469
.
33 m
3
.
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 Spring '10
 Gavrine
 Thermodynamics, Heat, Heat Transfer, 0.21 m, 0.0234 W

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