Chapter 17 - K sp = solubility product constant i Small K sp implies low solubility d K sp =[Pb 2[I 2 e g/L then[Equilibrium then K sp f.

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Chapter 17: Solubility I. Salts (Section 1, 3, 5) a. Pb(NO 3 ) 2 + 2KI yields PbI 2 + 2KNO 3 i. PbI 2 = insoluble, yellow b. K c2 (reverse reaction of solid going to ions) = K sp c.
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Unformatted text preview: K sp = solubility product constant i. Small K sp implies low solubility d. K sp = [Pb 2+ ][I-] 2 e. g/L then [Equilibrium) then K sp f....
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This note was uploaded on 01/27/2011 for the course CHEM 0120 taught by Professor Golde during the Spring '07 term at Pittsburgh.

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