3 Power factor compensation 2

# 3 Power factor compensation 2 - Lecture 5 Power factor...

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Lecture – 5 Power factor compensation (Lectures 2002 in the webpage). Power system dynamics. Load I + - Z Rj X =+ cos( ) cos Power Factor pf V I ϕ = ∠− = V I The goal of pf compensation is to modify the load, so that the compensated load has a new pf ; ' 1 pf ; We can have shunt or series compensation. Z X cc Z jX = + - + - V Series

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() cos sin VV V ZV I II I j Rj X ϕ ===∠− ∠=∠ =+ V R Zp f I ==• another way to write pf. As an exercise : Show G pf Y = ; Similarly, if the load consumes a given P & Q. P pf S = ; With a series compensation, Where : 22 c ZRX X + Z X cc Z jX = + - + - V '() ' ' c Z XX R pf Z + = YG j B = + Yj B = + - V parallel I
New pf : 22 ' () c c R pf RX X We need to make X X = ++ =− Example: jXc= -2j 1+2j V More generally, pf ‘ = 0.95 ; So in that case we have to solve the equation: ' c R pf X = ; And the other form of compensation : YG j B = + 2 5 c Yj = + - V 11 2 12 5 j Y j == + I

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Power System Dynamics : Consider the rotating mass of a large generator.
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## This note was uploaded on 01/27/2011 for the course ECSE 361 taught by Professor Franciscodgaliana during the Spring '09 term at McGill.

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3 Power factor compensation 2 - Lecture 5 Power factor...

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