Test3c_Spring_2009 - View Attempt 1 of 1 Title Started Submitted Exam 3 10:03 AM 11:17 AM 14/20 = 70 Total score adjusted by 0.0 Maximum possible

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View Attempt 1 of 1 Title: Exam 3 Started: April 28, 2009 10:03 AM Submitted: April 28, 2009 11:17 AM Time spent: 01:13:39 Total score: 14/20 = 70% Total score adjusted by 0.0 Maximum possible score: 20 1. Chapter 11 Ksp S 36 What is the solubility in moles/liter for chromium(III) iodate at 25 o C given a K sp value of 5.0 x 10 -6 . Write using scientific notation and use 1 or 2 decimal places (even though this is strictly incorrect!) Student Response Value Correct Answer 1. 2.1E-2 100% Equals 2.07e-2 (100%) Equals 2.1e-2 (100%) General Feedback: K sp = 27S 4 Score: 1/1 2. CIE 1 What is the solubility of silver iodide (K sp = 8.3 x 10 -17 ) in a solution of 0.20 M magnesium iodide? Student Response Value Correct Answer Feedback a. 2.1 x 10 - 16 100% b. 2.7 x 10 - 0%
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6 c. 4.2 x 10 - 16 0% d. 2.1 x 10 - 15 0% e. 9.1 x 10 - 9 0% Score: 0/1 3. Chapter 11 Precipitate 4 The K sp of AgCl at 25 o C is 1.6 x 10 -10 . Consider a solution that is 1.0 x 10 -4 M NaCl and 1.0 x 10 -6 M AgNO 3 . Student Response Value Correct Answer Feedback 1. Q > K sp and a precipitate will form. 0% 2. Q > K sp and a precipitate will not form. 0% 3. Q < K sp and a precipitate will not form. 100% 4. Q < K sp and a precipitate will form. 0% 5. The 0%
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saturated. Score: 1/1 4. Serial Precipitation 21 A solution is 0.40 M HgNO 3 and 0.30 M Pb(NO 3 ) 2 . If solid Na 2 CO 3 is added to the solution, what is [Pb 2+ ] when Hg 2 CO 3 begins to precipitate?(K sp PbCO 3 = 7.4 x 10 -14 ; Hg 2 CO 3 = 8.9 x 10 -6 ) Student Response Value Correct Answer Feedback a. 1.3 x 10 - 9 100% b. 3.0 x 10 - 3 0% c. 2.7 x 10 - 7 0% d. 5.6 x 10 - 5 0% e. 2.5 x 10 - 13 0% Score: 0/1 5. pH Solubility 3
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This note was uploaded on 01/29/2011 for the course CHEM 1332 taught by Professor Shiv during the Spring '08 term at University of Houston.

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Test3c_Spring_2009 - View Attempt 1 of 1 Title Started Submitted Exam 3 10:03 AM 11:17 AM 14/20 = 70 Total score adjusted by 0.0 Maximum possible

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