October 24, 2006
Corrections to Midterm # 2 solution:
Q1B.2:
There was a numerical error in the solution……
1,
2,
3,
1,
2,
3,
(
)
(0 1 3)
4
(
)
(1 4 1)
6
(
)
7.42
(
)
A
A
A
B
B
B
u
u
u
u
u
u
p A
e
e
e
p B
e
e
e
±
²
²
±
² ²
±
±
²
²
±
² ²
±
Q3B.3:
There was a numerical error in the solution……
10.5
7.5
3
2
2
181
2
AB
BC
L
L
#
Q4A:
W
left
=
8!
2!6!
= 28
W
right
=
4!
1!3!
= 4
W
total
= W
right
x W
left
= 28 x 4 = 112
If one move piston one to right, W
total,right
= 36 x 3 = 108
If one move piston one to left, W
total,left
= 21 x 5 = 105
The system is
at equilibrium
since entropy is maximized.
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October 24, 2006
Q4B:
There is an alternative way to solve this problem besides the solution provided and it
yields the same answer.
Compute entropy of both the left side and right side of the system A and B.
Compute
total entropy of systems A and B by adding the entropy of the left side and right side for
each respective system.
To calculate the change in entropy, simply subtract the total
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 Spring '09
 Kuryian
 Entropy, French Revolution, Leftwing politics

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