{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

E7Midterm 2 Solutions 2010(2)

# E7Midterm 2 Solutions 2010(2) - Contents Problem 1 Problem...

This preview shows pages 1–5. Sign up to view the full content.

Contents Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 format compact Problem 1 for i = 1:20 for j = 1:10 A(i,j) = sin(i*pi/4)*cos(j*pi/3); end end Problem 2 z = func2(3) z = 3 4 2 1 Problem 3 p = 3.5; q = 2; k = -5.5; p3i = (p + q) >= k p3ii = (p < 5) && (k > 0) p3iii = (p > q) || p < q p3iv = p + (q >= k) p3i = 1 p3ii =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
0 p3iii = 1 p3iv = 4.5000 Problem 4 u = [-3 0 0 2 5]; v = [-3 -2 0 2 4]; u < 0 v == u ans = 1 0 0 0 0 ans = 1 0 1 1 0 Problem 5 %two different examples of a correct solution are given below. type func3 function y = func3(month) switch lower(month) case {'january' 'march' 'may' 'july' 'august'... 'october' 'december'} y = 31; case {'april' 'june' 'september' 'november'} y = 30; case 'february' y = 28; otherwise error('not a valid month') end
Problem 6 type rec_sum3 function [Sn] = rec_sum3(n) if n == 1 Sn = 1; else Sn = rec_sum3(n-1) + n^3; end Problem 7 a7 = eps(1) < eps(100) b7 = eps(-1) < eps(1) c7 = eps(1) < realmin d7 = floor(-0.49) e7 = ceil(-0.49) f7 = round(-0.49) g7 = fix(-0.49) h7 = 1*2^1 + 1*2^0 + 1*2^-1 + 1*2^-2 i7 = 1111.11 a7 = 1 b7 = 0 c7 = 0 d7 = -1 e7 = 0 f7 = 0 g7 = 0 h7 =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}