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Unformatted text preview: E reaches zero. So, E(r) = 0 r<a Q(r) = 0 at r<aδ s Charge is accumulated at the outer surface ! 2 4 1   r Q E πε = r >a A conductor hollow sphere E(r) = ? 2D Problem in 3D Space x y z r Apply Coulomb’s Law =k e λ ∫ r /(x 2 +r ) 3/2 dx = 2k λ / r E + ∞∞ θ x Apply Gauss’s Law Solution Movie 5_3 Gauss‘s law in 1D q E= (q/ ε ) / 2 1D Problem in 3D Space x y z Apply Coulomb’s Law r =k e σ ∫ dx ∫ dy cos φ cos θ /(x 2 +y +r ) = k 2 π σ = σ / 2ε E + ∞∞ x + ∞∞ y Apply Gauss’s Law Φ E =E p A cylinder +2E n disc Constant! Parallel Plates ± The electric field is uniform in the central region, but not at the ends of the plates ± If the separation between the plates is small compared with the length of the plates, the effect of the nonuniform field can be ignored...
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 Fall '08
 NianLin
 Physics, Charge

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