quiz1pastpaper

quiz1pastpaper - -2V 1 1A + I 2 2A -6V - 10V 2 1A - 10V 4V...

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1 3 . In the circuit , find Io . Find also the power consumed or delivered by the 1A source . 1A Io 0 4 * Io 4V 2 * Io) 1A -10V 4V 2 * Io = = + = + + + + 0 ( 4V 2 1 - 10V 0A 1A A 2 A 1 2 Power for 1A = 1A*4V = 4W consumed 0V -6V -2V 4V 2V 4V 2 2 2 1 - 10V Io 1A I 1A + 1A 2 2A 0V 2A Apply KVL 1A 4V 2 2 2 1 - 10V Io 1A 0V 2A 4V 2V
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2 4 . When R = 0 , I3 = 14mA . When R = 1k , find V2. I1, V1 and I2 are unknowns . I2 1k V1 1k R 1k I1 When R = 0, I3 = 14mA Hence Isc = 14mA V2 1k 1k 1k b a b a R between ab = 1k Hence RN = 1k 1k 14mA 7V V = 2 R = 1k I2 1k V1 1k R 1k I1 V2 I3 b a
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5 . Use the Superposition Method to find Io . 3 3k 4k Io 20mA 6k mA 1 4k 6k 6k * mA 2 Io 2 0 = + = 6k 3k 2k 4k Io 14mA 2mA 12mA Io = + = Kill 20V Kill 20mA 6k 3k 2k 4k Io 20mA 20V 20V 2mA 4k 6k 20V Io = + = 6k 3k 2k 4k 14mA 20mA 20V 36V 56V 6mA 10mA 24mA
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This note was uploaded on 01/28/2011 for the course PHYS 011 taught by Professor Nianlin during the Fall '08 term at HKUST.

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quiz1pastpaper - -2V 1 1A + I 2 2A -6V - 10V 2 1A - 10V 4V...

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