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Unformatted text preview: CH 3 CH 3 H 3 C H OH H Now complete the chair pair using the forms given (which represent the "flip" due to rotation). DRAW BOTH AXIAL AND EQUATORIAL POSITIONS AT ANY RING ATOM THAT HAS A SUBSTITUENT (this is a general rule!) CH 3 OH H H 3 C Use both methods above to draw the conformational chair pair for this! CH 3 H CH 3 HO H 3 C H CH 3 H H 3 C OH CH 3 H becomes "foot" "head" each up becomes down But NOTE that the positions of the groups attached to the ring with respect to the ring and to each other (i.e. wedge, dash, which is an absolute stereochemical arrangement) do NOT change! methyl is still above the ring and above H since it is now on a "down" carbon, the methyl is equatorial above the ring. Different start postion rotation or "flip" H H 3 C CH 3 OH CH 3 OH H CH 3 CH 3 OH H CH 3 CH 3 OH H H 3 C...
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This note was uploaded on 01/28/2011 for the course CHEM 215 taught by Professor Koreeda during the Spring '07 term at University of Michigan.
- Spring '07