{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

ECE227 HW 6 Solutions

# ECE227 HW 6 Solutions - 2.14 a d = m i m i m 1 1 = ln L R i...

This preview shows pages 1–3. Sign up to view the full content.

2.14 a) m i m i d α α α η η + = = R L m 1 ln 1 α For L a = 500um and L p =500um: cm cm m / 39 . 11 32 . 1 ln 1 . 0 1 = = α cm L L L L p a ip p ia a i / 10 500 500 ) 5 )( 500 ( ) 15 )( 500 ( = + + = + + = α α α 3727 . 0 10 39 . 11 39 . 11 7 . 0 = + × = d η For L a = 500um cm cm m / 79 . 22 32 . 1 ln 05 . 0 1 = = α cm i / 15 = α 4221 . 0 15 79 . 22 79 . 22 7 . 0 = + × = d η For L a = 250um cm cm m / 58 . 45 32 . 1 ln 025 . 0 1 = = α 5266 . 0 15 58 . 45 58 . 45 7 . 0 = + × = d η b) m i th g α α + = Γ

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
cm g cm g cm g th th th / 757 08 . 58 . 45 15 ) 250 ( / 472 08 . 79 . 22 15 ) 500 ( / 8 . 534 2 1 08 . 10 39 . 11 ) 500 500 ( = + = = + = = × + = + 0 ) ( g g tr i i th th th e well J Wells of Number wL A J I = = η η ( 29 ( 29 mA e cm A wells cm cm I th 4 . 31 ) / 100 )( 6 ( 7 . 0 10 500 10 3 ) 500 500 ( 600 8 . 534 2 4 4 = × × = + - - ( 29 ( 29 mA e cm A wells cm cm I th 2 . 28 ) / 100 )( 6 ( 7 . 0 10 500 10 3 ) 500 ( 600 472 2 4 4 = × × = - - ( 29 ( 29 mA e cm A wells cm cm I th 7 . 22 ) / 100 )( 6 ( 7 . 0 10 250 10 3 ) 500 ( 600 757 2 4 4 = × × = - - c) ( 29 mA I I Hz I I qV a v f th th i g R 30 @ 10 5 2 1 9 2 / 1 = - × = - Γ = η π ( 29 ( 29 2 19 3 8 6 6 9 19 9 10 58 . 1 10 30 ) 7 . 0 ( 4 10 3 ) 2 / 1 )( 08 (.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern