ECE227 HW 6 Solutions

ECE227 HW 6 Solutions - 2.14 a) m i m i d + = = R L m 1 ln...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2.14 a) m i m i d + = = R L m 1 ln 1 For L a = 500um and L p =500um: cm cm m / 39 . 11 32 . 1 ln 1 . 1 = = cm L L L L p a ip p ia a i / 10 500 500 ) 5 )( 500 ( ) 15 )( 500 ( = + + = + + = 3727 . 10 39 . 11 39 . 11 7 . = + = d For L a = 500um cm cm m / 79 . 22 32 . 1 ln 05 . 1 = = cm i / 15 = 4221 . 15 79 . 22 79 . 22 7 . = + = d For L a = 250um cm cm m / 58 . 45 32 . 1 ln 025 . 1 = = 5266 . 15 58 . 45 58 . 45 7 . = + = d b) m i th g + = cm g cm g cm g th th th / 757 08 . 58 . 45 15 ) 250 ( / 472 08 . 79 . 22 15 ) 500 ( / 8 . 534 2 1 08 . 10 39 . 11 ) 500 500 ( = + = = + = = + = + ) ( g g tr i i th th th e well J Wells of Number wL A J I = = ( 29 ( 29 mA e cm A wells cm cm I th 4 . 31 ) / 100 )( 6 ( 7 ....
View Full Document

Page1 / 9

ECE227 HW 6 Solutions - 2.14 a) m i m i d + = = R L m 1 ln...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online