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Unformatted text preview: MTH 122 Calculus II Essex County College Division of Mathematics and Physics 1 Lecture Notes #21 Sakai Web Project Material 1 Representations of Functions as Power Series If you were to take the function f ( x ) = 1 1 x and carry out long division (well do this is class) youll see that it goes on forever and has a very nice pattern, namely f ( x ) = 1 + x + x 2 + x 3 + x 4 + = X n =0 x n . This, of course is the geometric series and it converges for  x  < 1. You should note that f ( x ) = 1 1 x is defined for all x 6 = 1, but for 1 < x < 1, f ( x ) can be written as a power series, X n =0 x n . Alhough f ( 2) = 1 / 3 and is easy to compute, we could not use the power series to compute this, because when x = 2 the series is not convergent. And even if we wanted to know f (1 / 2), which incidentally is 2, we wouldnt use the power series to do the computation. Rewriting functions as power series does have uses, but for now I am more concerned with finding a power series representation of a given function. Okay to better understand whats going on here, lets return to a problem from introductory calculus. The tangent line approximation L ( x ) is the best linear approximation to f ( x ) near x = a because f ( x ) and L ( x ) have the same rate of change (derivative) at a . For a better approximation than a linear one, lets try a seconddegree (quadratic) approximation P 2 ( x ). In other words, we approximate a curve by a parabola instead of by a straight line. To make sure the approximation is a good one, we stipulate the following: P 2 ( a ) = f ( a ) P 2 and f should have the same value at a . P ( a ) = f ( a ) P 2 and f should have the same value at a . P 00 2 ( a ) = f 00 ( a ) P 00 2 and f 00 should have the same value at a . This can, of course, go on ad infinitum . Lets take a concrete example. 1 This document was prepared by Ron Bannon ( ron.bannon@mathography.org ) using L A T E X2 . Last revised January 10, 2009. 1 1. Find the quadratic approximation P 2 ( x ) = A + Bx + Cx 2 to the function f ( x ) = e x that satisfies the above three conditions with a = 0. Graph P 2 and f on the same axis. Does P 2 fit f better than a tangent line in the region where a = 0? Work and Solution: We are given f ( x ) = e x and P 2 ( x ) = A + Bx + Cx 2 , and we need their derivatives. f ( x ) = e x f ( x ) = e x f 00 ( x ) = e x P 2 ( x ) = A + Bx + Cx 2 P 2 ( x ) = B + 2 Cx P 00 2 ( x ) = 2 C Now, using a = 0 we can determine the constants A , B and C . In the functions first. f (0) = e = 1 = P 2 (0) = A A = 1 Now in the first derivative. f (1) = e = 1 = P 2 (0) = B B = 1 Now in the second derivative....
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This note was uploaded on 01/31/2011 for the course MTH 222 taught by Professor Ban during the Spring '10 term at Essex County College.
 Spring '10
 Ban
 Calculus, Division, Power Series

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