SM_10A - y 1 0.33 = T 100 degC = Guess: x 1 0.33 = P 100...

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Unformatted text preview: y 1 0.33 = T 100 degC = Guess: x 1 0.33 = P 100 kPa = Given x 1 Psat 1 T ( ) 1 x 1- ( 29 Psat 2 T ( ) + P = x 1 Psat 1 T ( ) y 1 P = x 1 P Find x 1 P , ( 29 = x 1 0.169 = Ans. P 92.042kPa = Ans. (c) Given: x 1 0.33 = P 120 kPa = Guess: y 1 0.5 = T 100 degC = Given x 1 Psat 1 T ( ) 1 x 1- ( 29 Psat 2 T ( ) + P = x 1 Psat 1 T ( ) y 1 P = y 1 T Find y 1 T , ( 29 = y 1 0.542 = Ans. T 103.362degC = Ans. Chapter 10 - Section A - Mathcad Solutions 10.1 Benzene: A 1 13.8594 = B 1 2773.78 = C 1 220.07 = Toluene: A 2 14.0098 = B 2 3103.01 = C 2 219.79 = Psat 1 T ( ) e A 1 B 1 T degC C 1 +- kPa = Psat 2 T ( ) e A 2 B 2 T degC C 2 +- kPa = (a) Given: x 1 0.33 = T 100 degC = Guess: y 1 0.5 = P 100 kPa = Given x 1 Psat 1 T ( ) 1 x 1- ( 29 Psat 2 T ( ) + P = x 1 Psat 1 T ( ) y 1 P = y 1 P Find y 1 P , ( 29 = y 1 0.545 = Ans. P 109.119kPa = Ans. (b) Given: 270 x 1 y 1 Find x 1 y 1 , ( 29 = x 1 0.283 = Ans. y 1 0.485 = Ans. (f) z 1 0.33 = x 1 0.283 = y 1 0.485 = Guess: L 0.5 = V 0.5 = Given z 1 L x 1 V y 1 + = L V + 1 = L V Find L V , ( ) = Vapor Fraction: V 0.231 = Ans. Liquid Fraction: L 0.769 = Ans. (g) Benzene and toluene are both non-polar and similar in shape and size. Therefore one would expect little chemical interaction between the components. The temperature is high enough and pressure low enough to expect ideal behavior. (d) Given: y 1 0.33 = P 120 kPa = Guess: x 1 0.33 = T 100 degC = Given x 1 Psat 1 T ( ) 1 x 1- ( 29 Psat 2 T ( ) + P = x 1 Psat 1 T ( ) y 1 P = x 1 T Find x 1 T , ( 29 = x 1 0.173 = Ans. T 109.161degC = Ans. (e) Given: T 105 degC = P 120 kPa = Guess: x 1 0.33 = y 1 0.5 = Given x 1 Psat 1 T ( ) 1 x 1- ( 29 Psat 2 T ( ) + P = x 1 Psat 1 T ( ) y 1 P = 271 0.5 1 60 70 80 90 100 110 120 130 140 T x 1 ( 29 T x 1 ( 29 x 1 y' 1 x 1 ( 29 , 0.5 1 50 100 150 P x 1 ( 29 P x 1 ( 29 x 1 y 1 x 1 ( 29 , x 1 0 0.05 , 1.0 .. = y' 1 x 1 ( 29 x 1 Psat 1 T x 1 ( 29 ( 29 x 1 Psat 1 T x 1 ( 29 ( 29 1 x 1- ( 29 Psat 2 T x 1 ( 29 ( 29 + = T x 1 ( 29 root x 1 Psat 1 t ( ) 1 x 1- ( 29 Psat 2 t ( ) + P'- t , = t 90 = Guess t for root function: P' 90 = T-x-y diagram: y 1 x 1 ( 29 x 1 Psat 1 T ( ) P x 1 ( 29 = P x 1 ( 29 x 1 Psat 1 T ( ) 1 x 1- ( 29 Psat 2 T ( ) + = T 90 = P-x-y diagram: Psat 2 T ( ) exp A 2 B 2 T C 2 +- = Psat 1 T ( ) exp A 1 B 1 T C 1 +- = C 2 213.20 = B 2 3279.47 = A 2 14.0045 = C 1 220.07 = B 1 2773.78 = A 1 13.8594 = Antoine coefficients: Benzene=1; Ethylbenzene=2 (a) Pressures in kPa; temperatures in degC 10.2 272 0.5 1 70 77.5 85 92.5 100 107.5 115 122.5 130 T x 1 ( 29 T x 1 ( 29 x 1 y' 1 x 1 ( 29 , 0.5 1 20 66.67 113.33 160 P x 1 ( 29 P x 1 ( 29 x 1 y 1 x 1 ( 29 , x 1 0 0.05 , 1.01....
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This note was uploaded on 01/29/2011 for the course CHEM 101 taught by Professor Brown during the Spring '10 term at The University of Akron.

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SM_10A - y 1 0.33 = T 100 degC = Guess: x 1 0.33 = P 100...

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