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Unformatted text preview: Φ 2 P T , y 1 , y 2 , ( 29 exp B 22 P Psat 2 ( 29 ⋅ P y 1 2 ⋅ δ 12 ⋅ + R T ⋅ = Φ 1 P T , y 1 , y 2 , ( 29 exp B 11 P Psat 1 ( 29 ⋅ P y 2 2 ⋅ δ 12 ⋅ + R T ⋅ = δ 12 2 B 12 ⋅ B 11 B 22 = B 12 52 cm 3 mol ⋅ = B 22 1523 cm 3 mol ⋅ = B 11 963 cm 3 mol ⋅ = BUBL P calculations with virial coefficients: (b) y 1 x 1 ( 29 0.808 = P bubl x 1 ( 29 85.701kPa = x 1 0.75 = y 1 x 1 ( 29 0.731 = P bubl x 1 ( 29 80.357kPa = x 1 0.50 = y 1 x 1 ( 29 0.562 = P bubl x 1 ( 29 64.533kPa = x 1 0.25 = y 1 x 1 ( 29 x 1 γ 1 x 1 ( 29 ⋅ Psat 1 ⋅ P bubl x 1 ( 29 = P bubl x 1 ( 29 x 1 γ 1 x 1 ( 29 ⋅ Psat 1 ⋅ 1 x 1 ( 29γ 2 x 1 ( 29 ⋅ Psat 2 ⋅ + = BUBL P calculations based on Eq. (10.5): (a) Psat 2 37.31 kPa ⋅ = Psat 1 82.37 kPa ⋅ = γ 2 x 1 ( 29 exp x 1 2 A 21 2 A 12 A 21 ( 29 ⋅ 1 x 1 ( 29 ⋅ + ⋅ = γ 1 x 1 ( 29 exp 1 x 1 ( 29 2 A 12 2 A 21 A 12 ( 29 ⋅ x 1 ⋅ + ⋅ = Margules equations: T 55 273.15 + ( ) K ⋅ = A 21 1.42 = A 12 0.59 = 14.1 Chapter 14  Section A  Mathcad Solutions 463 y 1 y 2 P kPa 0.812 0.188 85.14 = y 1 y 2 P Find y 1 y 2 , P , ( 29 = y 2 1 y 1 = y 2 Φ 2 P T , y 1 , y 2 , ( 29 ⋅ P ⋅ 1 x 1 ( 29γ 2 x 1 ( 29 ⋅ Psat 2 ⋅ = y 1 Φ 1 P T , y 1 , y 2 , ( 29 ⋅ P ⋅ x 1 γ 1 x 1 ( 29 ⋅ Psat 1 ⋅ = Given x 1 0.75 = y 1 y 2 P kPa 0.733 0.267 79.621 = y 1 y 2 P Find y 1 y 2 , P , ( 29 = y 2 1 y 1 = y 2 Φ 2 P T , y 1 , y 2 , ( 29 ⋅ P ⋅ 1 x 1 ( 29γ 2 x 1 ( 29 ⋅ Psat 2 ⋅ = y 1 Φ 1 P T , y 1 , y 2 , ( 29 ⋅ P ⋅ x 1 γ 1 x 1 ( 29 ⋅ Psat 1 ⋅ = Given x 1 0.50 = y 1 y 2 P kPa 0.558 0.442 63.757 = y 1 y 2 P Find y 1 y 2 , P , ( 29 = y 2 1 y 1 = y 2 Φ 2 P T , y 1 , y 2 , ( 29 ⋅ P ⋅ 1 x 1 ( 29γ 2 x 1 ( 29 ⋅ Psat 2 ⋅ = y 1 Φ 1 P T , y 1 , y 2 , ( 29 ⋅ P ⋅ x 1 γ 1 x 1 ( 29 ⋅ Psat 1 ⋅ = Given x 1 0.25 = y 2 1 y 1 = y 1 0.5 = P Psat 1 Psat 2 + 2 = Guess: 464 Combining this with Eq. (12.10a) yields the required expression ln γ 1 ∞ A 12 = It follows immediately from Eq. (12.10a) that: (a) Psat 2 P 1 = x 2 1 x 1 = i 2 rows P ( ) .. = y 1 0.000 0.2716 0.4565 0.5934 0.6815 0.7440 0.8050 0.8639 = P 12.30 15.51 18.61 21.63 24.01 25.92 27.96 30.12 = x 1 0.000 0.0895 0.1981 0.3193 0.4232 0.5119 0.6096 0.7135 = Data: Pressures in kPa 14.4 Ans....
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This note was uploaded on 01/29/2011 for the course CHEM 101 taught by Professor Brown during the Spring '10 term at The University of Akron.
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