Φ
2
P T
,
y
1
,
y
2
,
(
29
exp
B
22
P
Psat
2

(
29
⋅
P y
1
2
⋅
δ
12
⋅
+
R T
⋅
=
Φ
1
P T
,
y
1
,
y
2
,
(
29
exp
B
11
P
Psat
1

(
29
⋅
P y
2
2
⋅
δ
12
⋅
+
R T
⋅
=
δ
12
2 B
12
⋅
B
11

B
22

=
B
12
52
cm
3
mol
⋅
=
B
22
1523

cm
3
mol
⋅
=
B
11
963

cm
3
mol
⋅
=
BUBL P calculations with virial coefficients:
(b)
y
1
x
1
(
29
0.808
=
P
bubl
x
1
(
29
85.701kPa
=
x
1
0.75
=
y
1
x
1
(
29
0.731
=
P
bubl
x
1
(
29
80.357kPa
=
x
1
0.50
=
y
1
x
1
(
29
0.562
=
P
bubl
x
1
(
29
64.533kPa
=
x
1
0.25
=
y
1
x
1
(
29
x
1
γ
1
x
1
(
29
⋅
Psat
1
⋅
P
bubl
x
1
(
29
=
P
bubl
x
1
(
29
x
1
γ
1
x
1
(
29
⋅
Psat
1
⋅
1
x
1

(
29
γ
2
x
1
(
29
⋅
Psat
2
⋅
+
=
BUBL P calculations based on Eq. (10.5):
(a)
Psat
2
37.31 kPa
⋅
=
Psat
1
82.37 kPa
⋅
=
γ
2
x
1
(
29
exp x
1
2
A
21
2
A
12
A
21

(
29
⋅
1
x
1

(
29
⋅
+
⋅
=
γ
1
x
1
(
29
exp
1
x
1

(
29
2
A
12
2
A
21
A
12

(
29
⋅
x
1
⋅
+
⋅
=
Margules equations:
T
55
273.15
+
(
) K
⋅
=
A
21
1.42
=
A
12
0.59
=
14.1
Chapter 14  Section A  Mathcad Solutions
463
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document