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Chem L2 - V= 0.0821(278.15)=22.4L STP=1atm and 0*C or...

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Chemistry 222 1/31/11 Midterm #2 Lecture #2 PV=nRT P= pressure, 1atm=760 mmHg V=volume in Liters n=amount in moles R=gas constant 0.0821 L*atm Mol*K T=temperature in Kelvin Ex: 1 mold He at 1atm and 273.15K
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Unformatted text preview: V= 0.0821(278.15)=22.4L STP=1atm and 0*C or 273.15 K “Special Cases” Before&after R=PV nT P 1 V 1 = P 2 V 2 N 1 T 1 N 2 T 2 µ rms = √ 3RTmolecular mass R=8.314 JKmol...
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