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2800labreport2 - pKa=pH-log[In[HIn A=bC AIn-AHIn=...

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= - [ -][ ] pKa pH log In HIn = A εbC - = - [ -][ ] AIn AHIn εIn εHInbb In HIn = + [ -][ ] pH pKa log In HIn - % actual experimentalactualx 100 = - [ -][ ] pKa pH log In HIn - = 10 pKa Ka = ± μ x tsn = - G questioned xs = . - - . - . - G 1 9x10 5 1 8x10 53 7x10 6 = . - ± . - . μ 1 8x10 5 3 7x10 62 3069 . = . - ( . ) 4 7 2 6 log 0 0079 - . = . - 10 4 7 1 9x10 5 . = . + . . 5 4 4 7 log5 01 0 . - - . - . - % 1 8x10 5 1 8x10 51 8x10 5x 100 . = . . . . 0 0079 0 006050 310945111 9x1044 7x104 . . - = . 0 2897541 5x10 5 1 9x104 Samples mL A mL B mL C mL D mL E xM HA 1.0 1.0 5.0 4.0 0.0 yM A- 1.0 5.0 1.0 4.0 0.0
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