EE 362 HOMEWORK 1 SOLUTION2010-02

# EE 362 HOMEWORK 1 SOLUTION2010-02 - EE 362 HOMEWORK 1...

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EE 362 HOMEWORK 1 SOLUTION a) number of slots s=24; p=4; s/p = 6 slots per-pole and q = 6/3=2 slots per-phase belt slot angle = 180/6 = 30 degrees electrical coil span = (5/6)*180 = 150 degrees (5 slots) winding diagram: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 a1 a2 -c1 -c8 b1 b2 -a3 -a4 c1 c2 -b3 -b4 a5 a6 -c3 -c4 b5 b6 -a7 -a8 c5 c6 -b7 -b8 a8 -c5 -c6 b7 b8 -a1 -a2 c7 c8 -b1 -b2 a3 a4 -c1 -c2 b3 b4 -a5 -a6 c3 c4 -b5 -b6 a7 1 1 0 0 0 0 -1 -1 0 0 0 0 1 1 0 0 0 0 -1 -1 0 0 0 0 1 0 0 0 0 -1 -1 0 0 0 0 1 1 0 0 0 0 -1 -1 0 0 0 0 1 b) MMF diagram for phase A current is I and other phases have no current Resultant field axis

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MMF diagram for phase A current is I and other phases have no current (All currents must be multiplied by turns per coil N/8 since each phase has 8 coils) c) MMF diagram at wt=0, all phases are excited by balanced 3 phase currents. (I a = I; I b = I c = -I/2) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 a1 a2 -c1 -c8 b1 b2 -a3 -a4 c1 c2 -b3 -b4 a5 a6 -c3 -c4 b5
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## This note was uploaded on 01/30/2011 for the course EE 362 taught by Professor Ermis during the Spring '10 term at Middle East Technical University.

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EE 362 HOMEWORK 1 SOLUTION2010-02 - EE 362 HOMEWORK 1...

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