Chap6MatBalTxt - Generalized Material Balances . . .Chap. 6...

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Unformatted text preview: Generalized Material Balances . . .Chap. 6 Review of equations and concepts Undersaturated reservoirs Saturated reservoirs Utility of Material Balances . . . Reserves . . . Recall Microscopic Balances... C j = concentrationof component j N j = fluxof component j j = oil , gas , water C j ( 29 t t + 1 r rN j ( 29 r r = Recall Macroscopic Balances V b C j ( 29 ( 29 t- V b C j ( 29 ( 29 t = = N Ij ( 29 sc- N pj ( 29 sc m j ( 29 t- m j ( 29 t = Present - Initial = N Ij ( 29 sc- N pj ( 29 sc In - Out Cumulative form of material balance Drive Mechanisms... OIL ZONE WATER (a) OIL ZONE GAS WATER WATER-INVADED ZONE (b) LIBERATED ORIGINAL WOC Water Influx At Discovery Drive Mechanisms... Gas Cap Expansion At Discovery OIL ZONE WATER GAS CAP (a) PRIMARY GAS CAP EXPANDED GAS CAP OIL ZONE WATER ORIGINAL GOC LIBERATED GAS (b) ORIGINAL WOC Drive Mechanisms... Solution Gas Drive At Discovery OIL ZONE WATER (a) OIL ZONE LIBERATED GAS WATER (b) Generalized Material Balances . . . Review of equations and concepts Total material balance equation Material Balance Equation The basic idea for primary depletion Initial pressure Lower pressure Volume of Reservoir temperature fluids produced volume of initial fluids Expanded Volume of initial fluids Fig. 6-1 Material Balance Equation G fgi E g free gas expansion 1 2 4 3 4 + N foi E o free oil expansion 1 2 4 3 4 + V pi S wi E w /B wi free water expansion 1 2 4 4 4 3 4 4 4 + W e water inf lux { = F V pi E f pore volume contraction 1 2 3 + Material Balance Equation F = underground withdrawal = G p- G I ( 29 B g- B o R v 1- R v R s net gas withdrawal 1 2 4 4 4 4 3 4 4 4 4 + N p B o- B g R s 1- R v R s net oil withdrawal 1 2 4 44 3 4 4 4 + W p- W I ( 29 B w net water withdrawal 1 2 4 4 3 4 4 Derivation.. 1. Write cumulative material balances for oil, gas, water. E.g. for oil 3. Identify terms . . . E.g. 2. Use saturation constraint to combine Given Data G I = ;W I = No gas, water injected: G p = 480 MCFgas N p = 419 STBoil W p = 6 . 31 MSTBwater Production data: B g = . 701 rbgas MCFgas B o = 1 . 371 rboleicphase STBoil R s = 801 SCFdissolvedgas STBoil R v = STBvolatileoil SCFgas PVT data (black oil) Example Calculation F = G p B g + N p B o- B g R s ( 29 + W p B w G p B g = 480 MCFgas ( 29 . 701 rbgas MCFgas G p B g = 336 rbgas Example Calculation F = G p B g + N p B o- B g R s ( 29 + W p B w B o- B g R s ( 29 = 1 . 371 rboleicphase STBoilgas- . 701 rbgas MCFgas 801 scf dissolvedgas STBoil 1 MCF 10 3 scf B o- B g R s ( 29 = 1 .....
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This note was uploaded on 01/30/2011 for the course PGE 323K taught by Professor Lake during the Spring '08 term at University of Texas at Austin.

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Chap6MatBalTxt - Generalized Material Balances . . .Chap. 6...

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