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Chap6MatBalTxt - Generalized Material Balances.Chap 6...

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Generalized Material Balances . . .Chap. 6 Review of equations and concepts Undersaturated reservoirs Saturated reservoirs
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Utility of Material Balances . . .
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Reserves . . .
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Recall Microscopic Balances...    C j = concentrationof component j    N j = fluxof component j    j = oil , gas , water    ∂ φ C j ( 29 t t + 1 r rN j ( 29 r r = 0
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Recall Macroscopic Balances    V b φ C j ( 29 ( 29 t - V b φ C j ( 29 ( 29 t = 0    = N Ij ( 29 sc - N pj ( 29 sc    m j ( 29 t - m j ( 29 t = 0 Present - Initial    = N Ij ( 29 sc - N pj ( 29 sc In - Out Cumulative form of material balance
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Drive Mechanisms... OIL ZONE WATER  (a) OIL ZONE GAS WATER  WATER-INVADED ZONE   (b) LIBERATED ORIGINAL     WOC Water Influx At Discovery
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Drive Mechanisms... Gas Cap Expansion At Discovery OIL ZONE WATER  GAS CAP (a) PRIMARY   GAS CAP  EXPANDED    GAS CAP OIL ZONE WATER  ORIGINAL     GOC LIBERATED GAS (b) ORIGINAL     WOC
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Drive Mechanisms... Solution Gas Drive At Discovery OIL ZONE WATER  (a) OIL ZONE LIBERATED GAS WATER  (b)
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Generalized Material Balances . . . Review of equations and concepts Total material balance equation
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Material Balance Equation The basic idea for primary depletion   Initial  pressure   Lower pressure Volume of Reservoir temperature fluids produced volume of initial fluids Expanded Volume of initial fluids Fig. 6-1
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Material Balance Equation G fgi E g free gas expansion 1 2 4 3 4 + N foi E o free oil expansion 1 2 4 3 4 + V pi S wi E w / B wi free water expansion 1 2 4 4 4 3 4 4 4 + W e water inf lux { = F V pi E f pore volume contraction 1 2 3 +
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Material Balance Equation F = underground withdrawal = G p - G I ( 29 B g - B o R v 1 - R v R s net gas withdrawal 1 2 4 4 4 4 3 4 4 4 4 + N p B o - B g R s 1 - R v R s net oil withdrawal 1 2 4 44 3 4 4 4 + W p - W I ( 29 B w net water withdrawal 1 2 4 4 3 4 4
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Derivation….. 1. Write cumulative material balances for oil, gas, water…. E.g. for oil 3. Identify terms . . . E.g. 2. Use saturation constraint to combine
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Given Data G I = 0 ;ŹW I = 0 No gas, water injected: G p = 480 ŹMCFŹgas N p = 419 ŹSTBŹoil W p = 6 . 31 ŹMSTBŹwater Production data: B g = 0 . 701 Ź rbŹgas MCFŹgas B o = 1 . 371 Ź rbŹoleicŹphase STBŹoil R s = 801 Ź SCFŹdissolvedŹgas STBŹoil R v = 0 Ź STBŹvolatileŹoil SCFŹgas PVT data (black oil)
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Example Calculation F = G p B g + N p B o - B g R s ( 29 + W p B w G p B g = 480 MCFŹgas ( 29 0 . 701 rbŹgas MCFŹgas G p B g = 336 ŹrbŹgas
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Example Calculation F = G p B g + N p B o - B g R s ( 29 + W p B w B o - B g R s ( 29 = 1 . 371 rbŹoleicŹphase STBŹoilŹgas - 0 . 701 rbŹgas MCFŹgasŹ 801 Ź scf ŹdissolvedŹgas STBŹoil 1 ŹMCF 10 3 scf B o - B g R s ( 29 = 1 . 371 rbŹoleicŹphase STBŹoilŹ - 0 . 561 rbdissolvedgas STBŹoilŹgas = 0 . 809 Ź rbŹoil STBŹoilŹ N p B o - B g R s ( 29 = 419 ŹSTBŹoil ( 29 0 . 809 Ź rbŹoil STBŹoilŹ
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Schematic of Reservoir . . .
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