{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

PGE 312_Spring10_Solution_HW6

# PGE 312_Spring10_Solution_HW6 - PGE 312 Physical and...

This preview shows pages 1–4. Sign up to view the full content.

PGE 312 Physical and Chemical Behavior of Fluids Home Work 6 Solutions Problem 6-4 Given: Example 3-6 Component Methane Standard Pressure, P sc = 14.7psia Temperature inside the container, T sc = 60 o F = 520 o R Mass of methane inside the container, m g = 10.2lb Solution: Using the ideal gas equation at standard conditions, we have P sc V sc = n g RT sc ----- (1) Molecular weight of methane, M= 16 ?? ?????? No. of moles of methane gas n g = ? ? ? = 10.2 16 = 0.6375 lb mole Substituting all the quantities in equation (1) we get V sc = 0.6375 10.732 520 14.7 = 242.02 scf Problem 6-9 Given: Example: 3-10 Pressure, P= 5014.7psia Temperature, T = 194 o F = 654 o R Solution: Formation volume factor B g = 0.02827 ?? 𝑃 ??? ?? . ?? ??? ---- (1)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
To find Z-factor at 5000psia and 654 o R: Component Mole fraction y j Critical Temperature, o R T cj y j T cj Critical Pressure, psia P cj y j P cj methane 0.9712 343.33 333.44 666.4 647.21 ethane 0.0242 549.92 13.31 706.5 17.10 propane 0.0031 666.06 2.06 616.0 1.91 i-butane 0.0005 734.46 0.37 527.9 0.26 n-butane 0.0002 765.62 0.15 550.6 0.11 hexane 0.0002 913.60 0.18 436.9 0.09 heptanes plus 0.0006 1082.00 0.65 372.0 0.22 1.0000 T pc 350.17 o R P pc 666.90 psia Calculate pseudoreduced properties, T pr = ? ? ?? = 654.0 350.2 = 1.87 P pr = 𝑃 𝑃 ?? = 5014.7 666.9 = 7.51 Using Fig. 3-7, we get Z = 1.02 Substituting back in equation (1) we get B g = 0.02827* 1.02 654 5014.7 = 3.818 x 10 -3 ??? 𝒄? . ?? ?𝒄? Problem 6-17 Given: Pressure, P = 900psia Temperature, T = 200 o F Pressure, psia Molar Volume, cu ft/lb mole 600 10.6 700 9.7 800 8.9 900 8.4 1000 8.1 1100 7.9 1200 7.8
Solution: Plotting the values we get, The coefficient of isothermal compressibility is given by equation (6-4) c g = 1 ?

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern