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# e2fall09 - MA 15400 Fall 2009 EXAM 2 Answers are on the...

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Unformatted text preview: MA 15400, Fall 2009 EXAM 2 Answers are on the last page. sin 2 θ + cos 2 θ = 1 1 + tan 2 θ = sec 2 θ 1 + cot 2 θ = csc 2 θ sin( u + v ) = sin u cos v + cos u sin v sin( u − v ) = sin u cos v − cos u sin v cos( u + v ) = cos u cos v − sin u sin v cos( u − v ) = cos u cos v + sin u sin v tan( u + v ) = tan u + tan v 1 − tan u tan v tan( u − v ) = tan u − tan v 1 + tan u tan v sin(2 u ) = 2sin u cos u cos(2 u ) = cos 2 u − sin 2 u tan(2 u ) = 2tan u 1 − tan 2 u A B C c a b α β γ MA 15400 Exam 2 Fall 2009 This exam covers all of Sections 6.7, 7.2, 7.3 7.4, and 7.6 2 1. A 25 foot ladder leans against the side of a 100 foot tall building. The angle between the ladder and the building is 23 ° . If the bottom of the ladder is then moved 2 feet closer to the building, to the nearest tenth of a degree, what is the angle that the ladder now makes with the side of the building? A. 28.1 ° B. 20.4 ° C. 18.1 ° D. 22.2 ° E. None of the above 2. Express as a trigonometric function of one angle. sin 43 cos17 cos43 sin17 ° ° − ° ° A. sin 26 ° B. cos60 ° C. sin 60 ° D. cos 26 ° E. None of the above 3. Given ABC △ with 90 γ = ° , express side a in terms of angle β and side b ....
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e2fall09 - MA 15400 Fall 2009 EXAM 2 Answers are on the...

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