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Unformatted text preview: if kT 6 B . 7.2 The energy distribution function The general form of the equilibrium velocity distribution function is P ( v x ,v y ,v z ) dv x dv y dv z = P ( v x ) dv x P ( v y ) dv y P ( v z ) dv z with P ( v i ) dv i = 1 exp -v 2 i 2 dv i where = 2 kT/m is the most probable velocity of a particle. The average velocity is given by v = 2 / , and v 2 = 3 2 2 . The distribution as a function of the absolute value of the velocity is given by: dN dv = 4 N 3 v 2 exp -mv 2 2 kT The general form of the energy distribution function then becomes: P ( E ) dE = c ( s ) kT E kT 1 2 s-1 exp -E kT dE where c ( s ) is a normalization constant, given by: 1. Even s : s = 2 l : c ( s ) = 1 ( l-1)! 2. Odd s : s = 2 l + 1 : c ( s ) = 2 l (2 l-1)!!...
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This note was uploaded on 01/30/2011 for the course PHYSICS 208 taught by Professor Ye during the Spring '10 term at Blinn College.
- Spring '10