This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: hussain (wh4892) hw 13 Opyrchal (121104) 1 This printout should have 16 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points An inductor has a 34 . 9 reactance at 90 . 2 Hz. What will be the peak current if this in ductor is connected to a 51 . 1 Hz source that produces a 47 . 8 V rms voltage? Correct answer: 3 . 41903 A. Explanation: Let : X L = 34 . 9 , f 1 = 90 . 2 Hz , f 2 = 51 . 1 Hz , and V rms = 47 . 8 V . The inductance is L = X L 2 f 1 = 34 . 9 2 (90 . 2 Hz) = 0 . 0615799 H . Thus, the rms current is I rms = V rms X L = V rms 2 f 2 L , so the maximum current is I max = 2 I rms = 2 V rms 2 f 2 L = 2 (47 . 8 V) 2 (51 . 1 Hz) (0 . 0615799 H) = 3 . 41903 A . 002 (part 1 of 2) 10.0 points In a purely inductive AC circuit, as in the figure, the maximum voltage is 120 V. L S E If the maximum current is 6 . 43 A at 50 Hz, find the inductance. Correct answer: 59 . 4046 mH. Explanation: Let : V max = 120 V , I 1 = 6 . 43 A , and f 1 = 50 Hz . The inductive reactance is X L = V I 1 = L = 2 f 1 suppressL , so the inductance is L = V 2 f 1 I 1 = 120 V 2 (50 Hz)(6 . 43 A) 10 3 mH H = 59 . 4046 mH . 003 (part 2 of 2) 10.0 points At what angular frequency is the maximum current 1 . 97 A? Correct answer: 1025 . 4 rad / s. Explanation: Let : I max = 1 . 97 A The inductive reactance is X L = V I 2 = 2 L, so the angular frequency is 2 = X L L = V I 2 L = 120 V (1 . 97 A)(59 . 4046 mH) 10 3 mH H = 1025 . 4 rad / s ....
View
Full
Document
This note was uploaded on 01/31/2011 for the course PHYS 111 taught by Professor Moro during the Spring '08 term at NJIT.
 Spring '08
 moro

Click to edit the document details