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solution14_pdf

# solution14_pdf - hussain(wh4892 – hw 14 – Opyrchal...

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Unformatted text preview: hussain (wh4892) – hw 14 – Opyrchal – (121104) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points In a certain series RLC circuit, the rms cur- rent is 10 . 3 A , the rms voltage is 130 V and the current leads the voltage by 37 ◦ . What is the total resistance of the circuit? Correct answer: 10 . 0799 Ω. Explanation: Let : I rms = 10 . 3 A , V rms = 130 V , and φ =- 37 ◦ . The average power delivered by the generator is dissipated as heat in the resistor: P av = I rms V rms cos φ = (10 . 3 A) (130 V) cos(- 37 ◦ ) = 1069 . 37 W , and the power dissipated in the resistor is P av = I 2 rms R, so the resistance is R = P av I 2 rms = 1069 . 37 W (10 . 3 A) 2 = 10 . 0799 Ω . 002 (part 2 of 2) 10.0 points Calculate the reactance X L- X C of the cir- cuit. Correct answer:- 7 . 59573 Ω. Explanation: For the reactance, tan φ = X L- X C R X L- X C = R tan φ = (10 . 0799 Ω) tan(- 37 ◦ ) =- 7 . 59573 Ω . 003 (part 1 of 2) 10.0 points In a series RLC circuit, the resistance is 57 Ω, the capacitance is 68 μ F and the inductance is 74 mH. The AC generator provides an...
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solution14_pdf - hussain(wh4892 – hw 14 – Opyrchal...

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