This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: maini (nm7637) hw5 Shneidman (12108) 1 This printout should have 15 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points The electron volt is a measure of 1. energy. correct 2. momentum. 3. velocity. 4. charge. 5. impulse. Explanation: Electron volt (eV) is a unit commonly used in atomic and nuclear physics. It is defined as the energy that an electron gains or loses by moving through a potential of 1 V. 002 10.0 points A dipole field pattern is shown in the figure. Consider various relationships between the electric potential at different points given in the figure. H J W T R + Notice: Five potential relationships are given below. a) V J = V T > V W b) V J = V T = V W c) V J = V T < V W d) V H < V W < V R e) V H > V W > V R Which relations shown above are correct? 1. ( e ) only 2. ( b ) and ( d ) only correct 3. ( d ) only 4. ( a ) only 5. ( c ) only 6. ( a ) and ( e ) only 7. ( b ) and ( e ) only 8. ( c ) and ( e ) only 9. ( c ) and ( d ) only 10. ( a ) and ( d ) only Explanation: The electric potential due to one single point charge at a distance r from the charge is given by V = k q r . For a dipole system, the total potential at any place is the sum of potentials due to one positive point charge and one negative point charge (Superposition Principle). From symmetry considerations, it is easy to see that the electric field lines are perpen dicular to a line which passes through the midpoint W and points J and T . No work needs to be done to move a positive test charge along the midplane because the force and the displacement are perpendicular to each other. V J = V W = V T , relation ( b ). Furthermore, moving along the direction of a electric field line ( i.e. , moving in the direc tion from positive charge to negative charge along the electric field line) always lowers the electric potential, because the electric field will do positive work to a positive test charge in order to lower its electric potential energy. Therefore, V H < V J by considering the line going from J to H , and V T < V R by consider ing the line going from R to T . maini (nm7637) hw5 Shneidman (12108) 2 V H < V W < V R , relation ( d ). The correct choices are ( b ) and ( d ) only. 003 (part 1 of 4) 10.0 points A uniform electric field of magnitude 302 V / m is directed in the positive xdirection. Sup pose a 19 C charge moves from the origin to point A at the coordinates, (25 cm, 59 cm)....
View
Full
Document
This note was uploaded on 01/31/2011 for the course PHYS 111 taught by Professor Moro during the Spring '08 term at NJIT.
 Spring '08
 moro
 Energy

Click to edit the document details